(2+5)/(3+12)+(6)/(7) - adding of fractions

(2+5)/(3+12)+(6)/(7) - step by step solution for the given fractions. Adding of fractions, full explanation.

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    Solution for the given fractions

    $ \frac{(2+5)}{(3+12)} +\frac{ 6}{7 }=? $

    The common denominator of the two fractions is: 105

    $ \frac{(2+5)}{(3+12)} = \frac{(7*(2+5))}{(7*(3+12))} =\frac{ 49}{105} $

    $ \frac{6}{7 }= \frac{(6*(3+12))}{(7*(3+12))} =\frac{ 90}{105} $

    Fractions adjusted to a common denominator

    $ \frac{(2+5)}{(3+12)} +\frac{ 6}{7 }=\frac{ 49}{105 }+\frac{ 90}{105} $

    $ \frac{49}{105 }+\frac{ 90}{105 }= \frac{(49+90)}{105} $

    $ \frac{(49+90)}{105 }=\frac{ 139}{105} $

    $ $

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