(2+5)/(3+12)+(6)/(7) - adding of fractions

(2+5)/(3+12)+(6)/(7) - step by step solution for the given fractions. Adding of fractions, full explanation.

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Solution for the given fractions

$\frac{(2+5)}{(3+12)} +\frac{ 6}{7 }=?$

The common denominator of the two fractions is: 105

$\frac{(2+5)}{(3+12)} = \frac{(7*(2+5))}{(7*(3+12))} =\frac{ 49}{105}$

$\frac{6}{7 }= \frac{(6*(3+12))}{(7*(3+12))} =\frac{ 90}{105}$

Fractions adjusted to a common denominator

$\frac{(2+5)}{(3+12)} +\frac{ 6}{7 }=\frac{ 49}{105 }+\frac{ 90}{105}$

$\frac{49}{105 }+\frac{ 90}{105 }= \frac{(49+90)}{105}$

$\frac{(49+90)}{105 }=\frac{ 139}{105}$



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