10(n-10)-7(2+3)=4n-4+10

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Solution for 10(n-10)-7(2+3)=4n-4+10 equation:



10(n-10)-7(2+3)=4n-4+10
We move all terms to the left:
10(n-10)-7(2+3)-(4n-4+10)=0
We add all the numbers together, and all the variables
10(n-10)-(4n+6)-75=0
We multiply parentheses
10n-(4n+6)-100-75=0
We get rid of parentheses
10n-4n-6-100-75=0
We add all the numbers together, and all the variables
6n-181=0
We move all terms containing n to the left, all other terms to the right
6n=181
n=181/6
n=30+1/6

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