1/5x+1/3y=14/15;1/5x+4y=78/5

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Solution for 1/5x+1/3y=14/15;1/5x+4y=78/5 system of equations:


  • /| (1/5)*x+(1/3)*y-(14/15) = 0| (1/5)*x+4*y-(78/5) = 0
  • We try to solve the equation: (1/5)*x+(1/3)*y-(14/15) = 0
  • 1/5*x+1/3*y-14/15 = 0 / - 1/5*x-14/15
  • 1/3*y = -(1/5*x-14/15) / : 1/3
  • y = (-(1/5*x-14/15))/1/3
  • y = 3*(14/15-(1/5*x))
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 3*4*(14/15-(1/5*x))+(1/5)*x-(78/5) = 0| y = 3*(14/15-(1/5*x))
  • 12*(14/15-1/5*x)+x/5-78/5 = 0
  • 56/5-11/5*x-78/5 = 0
  • -11/5*x-22/5 = 0
  • -11/5*x-22/5 = 0 / + 22/5
  • -11/5*x = 22/5 / : -11/5
  • x = 22/5/(-11/5)
  • x = -2
  • We insert the solution into one of the initial equations of our system of equations
  • For y = 3*(14/15-(1/5*x)):
  • y = 3*(14/15-(-2*1/5))
  • y = 3*(2/5+14/15)
  • y = 4/3*3
  • y = 4
  • We get a system of equations:
  • /| y = 4| x = -2

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