-(x-2)=3(y+1);2x+3=4y-1

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Solution for -(x-2)=3(y+1);2x+3=4y-1 system of equations:


  • /| 2-(3*(y+1))-x = 0| 2*x-(4*y)+1+3 = 0
  • We try to solve the equation: 2-(3*(y+1))-x = 0
  • 2-1*3*(y+1)-x = 0
  • 2-x-3*y-3 = 0
  • -x-3*y-1 = 0
  • -x-3*y-1 = 0 / + -x-1
  • -3*y = -(-x-1) / : -3
  • y = (-(-x-1))/(-3)
  • y = (x+1)/(-3)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 2*x-(4*((x+1)/(-3)))+1+3 = 0| y = (x+1)/(-3)
  • (-1*4*(x+1))/(-3)+2*x+1+3 = 0
  • 10/3*x+1+4/3+3 = 0
  • 10/3*x+7/3+3 = 0
  • 10/3*x+16/3 = 0
  • 10/3*x+16/3 = 0 / - 16/3
  • 10/3*x = -16/3 / : 10/3
  • x = -16/3/10/3
  • x = -8/5
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (x+1)/(-3):
  • y = (1-8/5)/(-3)
  • y = -3/5/(-3)
  • y = 3/5/3
  • y = 1/5
  • We get a system of equations:
  • /| y = 1/5| x = -8/5

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